135 lines
4.4 KiB
C
135 lines
4.4 KiB
C
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/*****************************************************************************
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根据战争策略游戏中的游戏号相关属性（账号、密码、金币数、vip等级、材料...）
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设计结构体的数据类型，实现以下的功能：
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1）注册账号 2）登录 3）设置账号的相关属性 4）显示
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*****************************************************************************/
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#include <stdio.h>
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#include <stdlib.h>
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#include <string.h>
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void Print_Guide()
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{
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printf("******************************\n");
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printf("请输入选项编号:\n");
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printf("******************************\n");
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printf(" 1 注册账号\n");
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printf(" 2 登录\n");
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printf(" 3 退出\n");
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printf("******************************\n");
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}
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void Print_UserOptions()
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{
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printf("******************************\n");
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printf("请输入选项编号:\n");
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printf("******************************\n");
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printf(" 1 设置账号属性\n");
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printf(" 2 显示用户属性\n");
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printf(" 3 退出至登录界面\n");
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printf("******************************\n");
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}
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struct Acount
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{
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char acount_name[20];
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char password[20];
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int gold;
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int vip_level;
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int material;
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};
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int main()
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{
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int login_option,user_option;
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char login_name[20];
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char login_password[20];
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struct Acount acount1;
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while(1)
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{
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Print_Guide();
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scanf("%d", &login_option);
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switch (login_option)
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{
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case 1:
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{
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printf("请输入账号名: ");
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scanf("%s", acount1.acount_name);
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printf("请输入密码: ");
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scanf("%s", acount1.password);
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printf("账号注册成功!\n");
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printf("账号名: %s\n", acount1.acount_name);
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printf("密码: %s\n", acount1.password);
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break;
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}
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case 2:
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{
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printf("请输入账号名: ");
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scanf("%s", login_name);
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if(strcmp(login_name,acount1.acount_name) != 0)
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{
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printf("账号不存在!\n");
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break;
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}
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else
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{
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printf("请输入密码: ");
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scanf("%s", login_password);
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if (strcmp(login_password, acount1.password) != 0)
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{
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printf("密码错误!\n");
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break;
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}
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else
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{
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printf("登陆成功!\n");
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while(1)
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{
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Print_UserOptions();
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scanf("%d", &user_option);
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switch (user_option)
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{
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case 1:
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printf("请输入金币数: ");
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scanf("%d", &acount1.gold);
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printf("请输入vip等级: ");
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scanf("%d", &acount1.vip_level);
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printf("请输入材料数: ");
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scanf("%d", &acount1.material);
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printf("账号属性设置成功!\n");
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break;
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case 2:
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printf("账号名: %s\n", acount1.acount_name);
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printf("密码: %s\n", acount1.password);
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printf("金币数: %d\n", acount1.gold);
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printf("vip等级: %d\n", acount1.vip_level);
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printf("材料数: %d\n", acount1.material);
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break;
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case 3:
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printf("已退出!\n");
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break;
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default:
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printf("无效选项!\n");
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}
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if(user_option == 3)
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break;
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}
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}
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}
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break;
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}
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case 3:
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printf("已退出!\n");
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break;
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}
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if(login_option == 3)
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break;
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}
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return 0;
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} |